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4-1.Newton's Laws of Motion
normal
Two blocks of $7\,\,kg$ and $5\,\,kg$ are connected by a heavy rope of mass $4\,\,kg.$ An upward force of $200\,N$ is applied as shown in the diagram. The tension at the top of heavy rope at point $P$ is ....... $N$ $(g = 10\,\,m/s^2)$
A$2.27$
B$112.5$
C$87.5$
D$360$
Solution
$200-160=16a$
$40=16 a$
$a=\frac{10}{4}=5 / 2$
$a=2.5 \mathrm{m} / \mathrm{s}^{2}$
$200-70-T=7 \times 9$
$130-T=7 \times 2.5$
$130-T=17.5$
$T=130-17.5$
$T=112.5 \mathrm{N}$
$40=16 a$
$a=\frac{10}{4}=5 / 2$
$a=2.5 \mathrm{m} / \mathrm{s}^{2}$
$200-70-T=7 \times 9$
$130-T=7 \times 2.5$
$130-T=17.5$
$T=130-17.5$
$T=112.5 \mathrm{N}$
Standard 11
Physics
